Question
7.1.9 @DateTime.TimeDifference returns invalid date time string that can not be assigned to a DateTime property
I was trying to set a DateTime type property using declare expression like below, however the expression fails because @DateTime.TimeDifference function returns invalid date time string.
.ToDate =@DateTime.TimeDifference(.FromDate,7,0,0,0)
FAIL
Step Status Info
** Invalid datetime format/Invalid datetime "Fri 2016/03/04 22:31:00 GMT+00:00"
Is this a known issue? or is it designed to return a date time string that can not be directly assigned to a DateTime type property?
Hi Chunzhi,
The return type of the TimeDeferance function will be pf String which will be in the format which is mentioned by you.
If this is your requirement to add a specific number of days, hours, mins, seconds to calculate a new date, then you can use the function "addToDate" in date time library.
Thanks.
I guess DateTime type in Pega expects a date time string in GMT with ISO format.
Then why not any function returns a date time string simply returns a Pega DateTime compatible string and leave the formatting issue to the caller of that function? What is the benifit of returning a string that doesn't compatible with DateTime type?