Unzip file from S3 pegacloudfilestorage
Hello,
we are trying to extract files from a ZIp file we have stored in S3 pegacloudfilestorage. At this moment, we are strugling to define the best approach to:
- pick the zip (we are using the API D_pxGetFile
- open the Zip and save the files - this is the tricky part as we have have seen some java code that may help us but we are not on the best approach as we have already tried some options and we allways get to the no such file or directory log message..
If someone has done this asn can point us on the correct document/article it would be great.
Thank you.
Hi,
It would be really helpful if you can share the Java code fragment that you are using to unzip the file through which the issue can be identified.
But below is a suggested solution that can be tried:
D_pxGetFile provides the base64Encoded string which is in essence encoded form of ByteArray of the file, so to reuse the String in Java code we first need to decode the string into a byte array and then we can use it further in Java code.
String fileContent = D_pxGetFile.pyContent;
byte[] fileBytes = Base64.decode(fileContent);
ZipInputStream zipStream = new ZipInputStream(new ByteArrayInputStream(bytes));
ZipEntry entry = null;
while ((entry = zipStream.getNextEntry()) != null) {
String entryName = entry.getName();
FileOutputStream out = new FileOutputStream(entryName);
byte[] byteBuff = new byte[4096];
int bytesRead = 0;
while ((bytesRead = zipStream.read(byteBuff)) != -1)
{
out.write(byteBuff, 0, bytesRead);
}
out.close();
zipStream.closeEntry();
}
zipStream.close();
Here the zipentries have been transformed into a FileOutputStream.Now I am not using this output stream in any way in the above code snippet but we can use this stream for further processing according to the use-case.
Please do raise any further queries.
Happy Coding!!
Hello ShikharA ,
Thank you for answering.
In the mean time we managed to get to a similar approach. Bellow you can see our code:
Hello ShikharA ,
Thank you for answering.
In the mean time we managed to get to a similar approach. Bellow you can see our code:
java.io.InputStream initialStream =(java.io.InputStream)myStepPage.getObject("pyStream");
java.util.zip.ZipInputStream zipInputStream = new java.util.zip.ZipInputStream(initialStream);
String destinationDir=pega.getSystemSettings().getDynamic("MOOFW", "IQB/ScssFilesZip"); // to update output directory
try{
oLog.infoForced("Opening Zip File");
byte[] buffer = new byte[1024];
String fileName = "";
String initialname= "IQB_";
java.util.zip.ZipInputStream zis= zipInputStream;
//java.io.InputStream unZipInputStr;
java.util.zip.ZipEntry zipEntry;
int len;
int count = 0;
while((zipEntry = zis.getNextEntry()) != null)
{
oLog.infoForced("File number---" + Integer.toString(count));
fileName = zipEntry.getName();
oLog.infoForced("Processing file ---" + initialname + fileName);
PRFile destFile = new PRFile(destinationDir + initialname + fileName);
PRFile newFile = destFile;
PROutputStream fos = new PROutputStream(newFile);
if (!zipEntry.isDirectory())
{
while((len = zis.read(buffer)) > 0)
{
fos.write(buffer, 0, len);
}
fileName = "";
fos.close();
oLog.infoForced("Ended Processing file ---" + fileName);
}
zis.closeEntry();
count = count + 1;
}
zis.closeEntry();
zis.close();
zipInputStream.close();
}
catch (java.io.IOException e)
{
e.printStackTrace();
oLog.error(e);
}Thank you for the support.