Two Cases Problem
Hi Everybody,
I'm just trying to find out how to solve a problem, if one case calls one subcase without waiting for it!
I have built two applications, app P and App C. App C is called within App P. At the moment case CP of app P waits until case CC of app C is finished right after calling it.
App C calls an external service with a Connect SAOP and gets back an ID as response. It may be that the external service provider is not available and returns no ID.
So case CP of app P have not to wait and can go on to the end of the process.
However it must be assured that it is possible that the ID will be received at a later time/date and it must be deposited in the workobject of case CP.
The Problem is that case CP could already be finished.
How can I guarantee, that there is still a connect to both after CP is finished?
One consideration was that case CP is waiting at the end of the process too all open sub-cases with spinoff flow, but I do not know how it behaves, if I have several sub-cases.
Thanks in advance
Accepted Solution
Pegasystems
US
I'll answer part of it: You can use the "spinoff" attribute on your subprocess call in a flow which means call the subflow but don't wait for it to finish. Could someone else please explain the related crucial part which is, ok, so we've previously done a spinoff because we wanted to launch the subprocess and not wait for it to finish, but that was earlier, and now we want to wait for that that previously-spun-off subprocess to finish. How do we wait ? /Eric
Hi Norman,
If you just want to update a property then you can update that in the resolved case directly by opening the resolved CP case obj-open and obj-save.
If you need the flow for CP case to wait then the consideration that you say should work fine
Amit