Here we can see how to pass the Rest url dynamically and get the response.

1) first create one windows for with one label, textbox and button. [See the attachment]

2) create an automation file [see the attachment]

3) Made the below changes in Script.

using System;

using System.Collections;

using System.Data;

using System.Diagnostics;

using System.IO;

using System.Linq;

using System.Windows.Forms;

using System.Xml;

using System.Collections.Generic;

using System.Net;

using System.Text;

namespace Dynamic.Script_8D5A918544C6840

{

// Script generated by Pega Robotics Studio 8.0.1064.0

// Please use caution when modifying class name, namespace or attributes

[OpenSpan.TypeManagement.DynamicTypeAttribute()]

[OpenSpan.Design.ComponentIdentityAttribute("Script-8D5A918544C6840")]

public sealed class Script

{

public void RestCall (string url, out string outresponse)

{

HttpWebRequest request = (HttpWebRequest)WebRequest.Create(url);

request.Method = "GET";

request.ContentType ="application/json";

request.Accept = "application/json";

ServicePointManager.SecurityProtocol = SecurityProtocolType.Tls12;

string response = GetRESTResponse(request);

outresponse = response;

}

public string GetRESTResponse(HttpWebRequest request)

{

string restResponse = string.Empty;

using (HttpWebResponse response = (HttpWebResponse)request.GetResponse())

{

if (response.StatusCode == HttpStatusCode.OK)

{

using (Stream responseStream = response.GetResponseStream())

{

if (responseStream != null)

{

StreamReader reader = new StreamReader(responseStream);

restResponse = reader.ReadToEnd();

}

}

}

}

return restResponse;

}

}

}

***Updated by moderator: Lochan to mark post as discussion and Community Shared Knowledge***