how to covert julian date to normal date format for example: juliandate- 2013123 should be as 3 May, 2013 or yyyymmdd format
how to covert julian date to normal date format for example: juliandate- 2013123 should be as 3 May, 2013 or yyyymmdd format
Message was edited by: Lochan to add Category
Accepted Solution
Pegasystems Inc.
IN
Pegasystems Inc.
US
Hi Vineetha,
I am not sure about the OOTB rule to convert the Julian date into the regular date format, but I had written a code to convert the Julian date into the normal date as follows:
Code:
String input = "1999046";
DateFormat fmt1 = new SimpleDateFormat("yyyyDDD");
Date date = fmt1.parse(input);
DateFormat fmt2 = new SimpleDateFormat("MM/dd/yyyy");
String output = fmt2.format(date);
System.out.println(output);
Output: 02/15/1999
Hope this might help you in achieving your requirement.
Regards,
Mahesh
Pegasystems Inc.
IN
Thanks Mahesh for your reply
Do you know any OOTB or java code to convert normal date to Julian date
Pegasystems Inc.
US
Hi Vineetha,
I am not aware of the OOTB rule to perform this functionality so i had suggested you to do this using Java code.
Regards,
Mahesh
Accepted Solution
Pegasystems Inc.
IN
Hi ,
I had done using pega functions only.
@(Pega-RULES:DateTime).DateTimeDifference(@(Pega-RULES:String).toDate(Param.Input),@(Pega-RULES:String).toDate("20160621"), "D")
@(Pega-RULES:String).substring( @(Pega-RULES:DateTime).CurrentDateTime(), 0, 4)+"0101"
Hi ,
I had done using pega functions only.
@(Pega-RULES:DateTime).DateTimeDifference(@(Pega-RULES:String).toDate(Param.Input),@(Pega-RULES:String).toDate("20160621"), "D")
@(Pega-RULES:String).substring( @(Pega-RULES:DateTime).CurrentDateTime(), 0, 4)+"0101"